Еп. 4: Сакута стикається з часовою петлею 27 червня, намагаючись розібратися зі своїми почуттями до Май та складною ситуацією Томо

On June 27, Sakuta proceeds through his day by eating lunch with Mai, who accepts his feelings for her, and encountering Tomoe being asked out by Maezawa, a member of the basketball club. However, June 27 begins to repeat as Sakuta finds himself stuck in a time loop, which Rio attributes to the phenomenon of Laplace's demon. To break out of the loop, she suggests he try to find whoever is not behaving the same as the day repeats, leading him to Tomoe. While hiding in a desk, Tomoe explains her best friend had a crush on Maezawa, hence her reluctance. Sakuta and Tomoe eventually fall on top of each other, angering Maezawa and Mai when they spot the two. The loop eventually ends, but Mai does not show up to school the next day. Tomoe later proposes she and Sakuta enter a fake relationship until the start of summer break. Sakuta agrees after seeing Tomoe's distress at the thought of her losing her friends and comparing this to how his sister, Kaede felt when a similar occurrence happened to her. Later that night, as Sakuta is trying to figure out how to explain the situation to Mai, Mai surprisingly comes to his apartment and asks why he hadn't come to explain himself yet about Tomoe. (Source: Wikipedia)

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